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4 years ago

5^3x 5^x= 5^7 Find the value of x.

Mathematics

2 answers:

m_a_m_a [10]4 years ago

7 0

Answer:

x= 5^4-x

Step-by-step explanation:

slega [8]4 years ago

4 0

So,the right answer is 4.

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Patrick leaves for lunch at 12:36. He has 50 minutes to eat. What time must he be back?

yarga [219]

Patrick must be back by 1:26

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3 years ago

Help me plz thx so much

rewona [7]

She paid $30 bucks total.

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3 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

3 years ago

a random sample of size 200 is drawn from a large population. The population standard deviation is 1.2. The sample mean is 15.8.

Marrrta [24]

Step-by-step Answer:

N=sample size = 200

sigma = population standard deviation = 1.2

s=Sample mean = 15.8

Best estimate of population mean = 15.8

standard error = sigma / sqrt(N)

= 1.2/sqrt(200)

= 0.08485

Therefore

estimate of population mean = 15.8 +/- 0.0848

3 0

4 years ago

Tessa bought stock in a restaurant for $151.00. Her stock is now worth $196.30. What is the percentage increase of the value of

goldenfox [79]

I believe the answer is C. I’m terribly sorry if I got it wrong

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3 years ago