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3 years ago

Directions for constructing the in-center of a triangle?

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

Answer:

HERE YOU GOOO!!!!!

Step-by-step explanation:

1. locate the incenter by constructing the angle bisectors of at least two angles of the triangle.

2. construct a perpendicular from the incenter to one side of the triangle to locate the exact radius.

3. place compass point at the incenter and measure from the center to the point where the perpendicular crosses the side of the triangle (the radius of the circle).

4. draw the circle.

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Ms. Bell's mathematics class consists of 14 sophomores, 6 juniors, and 10 seniors.How many different ways can Ms. Bell create a

prohojiy [21]

Ms. Bell's mathematics class consists of 14 sophomores,

Ms. Bell create a 4-member committee of sophomores

if each sophomore has an equal chance of being selected

this is a combination

$\begin{gathered} ^{14}C_4=\frac{14!}{4!(14-4)!} \\ =\frac{14!}{14!\times10!} \\ =1001 \end{gathered}$

The answer is 1001.I’ve completed answering the question.

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1 year ago

1/2r + 2(3/4r - 1) = 1/4r + 6

taurus [48]

$\frac{1}{2}r+2(\frac{3}{4}r-1)=\frac{1}{4}r+6\ \ \ \ \ \ \ |omit\ bracket\\\\\frac{1}{2}r+\frac{3}{2}r-2=\frac{1}{4}r+6\ \ \ \ \ \ |\cdot4\\\\2r+6r-8=r+24\ \ \ \ \ \ |combine\ like\ terms\\\\2r+6r-r=24+8\ \ \ \ \ |simplify\\\\7r=32\ \ \ \ \ |:7\\\\r=\frac{32}{7}=4\frac{4}{7}$

3 0

3 years ago

Read 2 more answers

Can anyone help me please thank you

andreev551 [17]

Answer:

The first option

Step-by-step explanation:

Because when you multiply the first equation by 2, it sets the -x to -2x which helps cancel the variable out allowing you to easily solve the system of equations.

6 0

3 years ago

Read 2 more answers

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

8 0

2 years ago

Math help anyone please help! :)) will give brainliest

Mice21 [21]

1st find the slope m.
m= (rise)/(run). Look up the graph and notice that the rise is 1 for a run =5
Then the slope will be 1/5
2 lines are parallel if they have the same slope so it's either
y= 1/5 x + 4 or 1/5 x + 12/5
our function is y = mx + b, but we know that m = 1/5
so the equation is y = 1/5 x + b
and we know that the function passes through the point (-2,2)
To calculate b, plug in y= 1/5 x + b , x & y by their respective values:
2 = (1/5) (- 2) + b
2 = - 2/5 + b and b = 12/5, then the equation is Y= 1/5 X + 12/5

8 0

3 years ago

Directions for constructing the in-center of a triangle?​

Directions for constructing the in-center of a triangle?