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Alika [10]
3 years ago
14

(74pts) I offer all my points to anyone but help me! Write a real-world problem that can be represented by the algebraic equatio

n shown.
5x + 6 = 66
Mathematics
2 answers:
Neko [114]3 years ago
8 0
Real world example:
Lily needs to sell 66 tickets.  She has already sold 6, and has to sell the rest in groups of 5.  How many groups does she need to sell to meet her goal?

5x + 6 = 66
5x +6 - 6 = 66 - 6
5x = 60
5x/5 = 60/5 
x = 12

Lily needs to sell 12 more groups of her bundles to meet her goal.

musickatia [10]3 years ago
3 0
<span>Jane is playing a game with Mike. Right now, Mike is winning, he has 10 more than 5 times the points that Jane has. If Jane has 47 points, how many points does Mike have?

or you could do 

</span><span>Martha is doing an inventory of all the goods in her shop. For the brand Toms shoes, she should have recieved an order that would have brought the total number of Toms shoes in her store to 10 more than 5 times the number of shoes she has now. If Martha has 89 pairs of Toms in her store, how many would she have had, if she had recieved the delivery?

hope this helped :)
alisa202</span>
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Whats 753×5648÷-4519
SIZIF [17.4K]

Answer:

It equals -941.12.... There is a thing caled a calculator you can use for that ;D

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
In a poll of travelers, 85% said that traveling by air makes them nervous, and 450 travelers said that it does not make them ner
OverLord2011 [107]
The answer is 1,338 were polled
5 0
3 years ago
Read 2 more answers
Hello Brainly Teacher Brainly Moderators and trusted helpers!​
tatyana61 [14]

Answer:

  • P(x < 84) = 0.3085 or approximately 31%

============

<em>Hello to you from Brainly team!</em>

<h3>Given</h3>

  • Mean grade μ = 86,
  • Standard deviation σ = 4,
  • Grade limit x = 84.

<h3>To find </h3>

  • Probability of that a randomly selected grade is less than 84 or P(x < 84).

<h3>Solution</h3>

Find z-score using relevant equation:

  • z = (x - μ)/σ

Substitute values and calculate:

  • z = (84 - 86)/4 = - 0.5

Using the z-score table find the corresponding P- value.

  • P(x < 84) = 0.30854 or approximately 31%
4 0
1 year ago
In a movie theater, the first row contains 3 seats, the second row contains 6 seats, the third row contains 9 seats, and the fou
yanalaym [24]

Answer:It's an arithmetic sequence with a common difference, d, = 4

A1 = 8

A2 = 8+4 = 12

A3 = 12+4 = 16   = 8+4(3-1) = 8+4(2) = 8+8

AN = A1 + d(N-1)

AN = 8 +4(N-1)  =  the Nth term in the sequence

Step-by-step explanation: hoped it helped

7 0
2 years ago
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