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2 years ago

I need help with #2 and 3, any help?

Mathematics

2 answers:

Setler [38]2 years ago

6 0

2) y=mx+b
y=-1/2x-2
b=-2 & m= -1/2 down negative one, right two (+)

zubka84 [21]2 years ago

6 0

2. y=-1/2 +2
3. y=3/2 +1

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If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)

erica [24]

Given:

Given that ABCD is a rectangle.

The diagonals of the rectangle are AC and DB.

The length of AE is (6x -55)

The length of EC is (3x - 16)

We need to determine the length of the diagonal DB.

Value of x:

The value of x can be determined by equating AE and EC

Thus, we have;

$AE=EC$

Substituting the values, we get;

$6x-55=3x-16$

$3x-55=-16$

$3x=39$

$x=13$

Thus, the value of x is 13.

Length of AC:

Length of AE = $6(13)-55=78-55=23$

Length of EC = $3(13)-16=39-16=23$

Thus, the length of AC can be determined by adding the lengths of AE and EC.

Thus, we have;

$AC=AE+EC$

$AC=23+23$

$AC=46$

Thus, the length of AC is 46.

Length of DB:

Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.

Hence, we have;

$AC=DB$

$46=DB$

Thus, the length of DB is 46.

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2 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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We know that the perimeter, p, is 58, and the length/height is 18. Therefore, we can substitute those values in

58=2(18)+2w

Multiply 2 and 18

58=36+2w

Since we want to find the width, we need to get w by itself. First, subtract 26 from both sides

58-36=36-36+2w

22=2w

Since w is being multiplied by 2, divide both sides by 2. This will cancel out the 2, and leave w by itself.

22/2=2w/2

11=w

So, the width is 11 inches

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Answer:

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