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ahrayia [7]
3 years ago
15

Solve the following:a4x - 3 = 2x + 7what does x equal​

Mathematics
2 answers:
Serga [27]3 years ago
5 0

Answer:

x=5

Step-by-step explanation:

4x-3=2x+7

4x-2x-3=7

4x-2x=7+3

2x=10

2x/2 10/2

x=5

8_murik_8 [283]3 years ago
3 0

Answer:

x=5

Step-by-step explanation:

So we have to combine like terms

4x-3=2x+7

-2x  -2x

2x-3=7

   +3 +3

And now simplify

2x=10

/2   /2

x=5

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If f(x)=x+8 and g(x)=-4x-3 find (f+g)(x)
nydimaria [60]

Answer:

for this case we have the following functions:

f (x) = x + 8

g (x) = -4x - 3

Subtracting the functions we have:

(f - g) (x) = f (x) - g (x)

(f - g) (x) = (x + 8) - (-4x - 3)

Rewriting:

(f - g) (x) = x + 8 + 4x + 3

(f - g) (x) = 5x + 11

Answer:

D. (f - g) (x) = 5x + 11

7 0
3 years ago
Pamela is 12 years younger than Jiri. The sum of their ages is 80. What is Jiri's age?<br> years old
vfiekz [6]
80/2= 40
46-34= 12
So Pamela is 34 & Jiri is 46
7 0
3 years ago
The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu
mart [117]

Answer:

The shaded area is 23\ in^{2}

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

so

A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})

Calculate the shaded area

Remember that

3^{2}=9\\ 2^{2}=4

substitute

A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}

5 0
3 years ago
How to solve this inequality -8×+18&gt;-22
Ksju [112]

Answer:

x < 5

Step-by-step explanation:

<u>Step 1:  Solve for x</u>

-8x + 18 > -22

-8x + 18 - 18 > -22 - 18

-8x / -8 > -40 / -8

<em><u>When dividing by negative, it flips the sign</u></em>

x < 5

Answer: x < 5

4 0
3 years ago
Multiply the polynomials (5x^2+4x-4)(4x^3-2x+6)<br> Explain your steps!!
Lapatulllka [165]
So distribute using distributive property
a(b+c)=ab+ac so

split it up
(5x^2+4x-4)(4x^3-2x+6)=(5x^2)(4x^3-2x+6)+(4x)(4x^3-2x+6)+(-4)(4x^3-2x+6)=[(5x^2)(4x^3)+(5x^2)(-2x)+(5x^2)(6)]+[(4x)(4x^3)+(4x)(-2x)+(4x)(6)]+[(-4)(4x^3)+(-4)(-2x)+(-4)(6)]=(20x^5)+(-10x^3)+(30x^2)+(16x^4)+(-8x^2)+(24x)+(-16x^3)+(8x)+(-24)
group like terms
[20x^5]+[16x^4]+[-10x^3-16x^3]+[30x^2-8x^2]+[24x+8x]+[-24]=20x^5+16x^4-26x^3+22x^2+32x-24

the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24




4 0
3 years ago
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