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Ann [662]
3 years ago
5

What information can be used to compare linear relationships? Explain why.

Mathematics
2 answers:
seropon [69]3 years ago
6 0

Answer: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

Step-by-step explanation: Sample Response on Edge

kiruha [24]3 years ago
3 0
The slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).
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Please solve this problem tnx....​
True [87]

Answer:

27.50

Step-by-step explanation:

Since it is 16.50 each and they bought 5 packets total an easy way to solve this problem would be that you multiply 16.50 × 5 which will give you how much the total cost of the candy would be:

16.50 × 5 = 82.50

Since that is the total amount you would then divide 82.50 by 3 since Mary and her friends all split the cost three ways (since there are three of them):

82.50 ÷ 3 = 27.50

Which will give you your answer.

7 0
3 years ago
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
Which number line shows the solution of 5x- 25 &lt;-15?
Elena L [17]

Answer

to solve for x is 8

Step-by-step explanation:

Did this help??????

8 0
2 years ago
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What function is graphed below? <br> A. y=-x^2<br> B. y=x^2<br> C. y=x^3<br> D. y=-x^3
elena55 [62]
The answer is A. The graph is an X^2 graphed but when you add the negative it flips the graph over the y-axis.
4 0
3 years ago
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Help 5 minutes!!! I’m giving 50 points
tekilochka [14]

Answer:

5 - 3×1= -8

I think

6 0
3 years ago
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