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4 years ago

What information can be used to compare linear relationships? Explain why.

2 answers:

6 0

Answer: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

Step-by-step explanation: Sample Response on Edge

kiruha [24]4 years ago

3 0

The slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).

You might be interested in

Factor the following expression: x2-4x-21

natka813 [3]

Answer:

(x − 7)(x + 3)

Step-by-step explanation:

Step 1: You need to find out what to numbers add up to −4 and multiply −21?

−7 and 3

Step 2: Just rewrite the expression using the above and you're done!

(x − 7)(x + 3)

3 0

3 years ago

What is the product of 6 and n

faust18 [17]

Answer:

6n

Step-by-step explanation:

Lesson: ⇒ Algebric Expression

Product: ⇒ multiply

6n is the correct answer.

I hope this helps you, and have a wonderful day!

4 0

3 years ago

Eli claims that the product of and is . Which explains whether Eli is correct?

Shalnov [3]

Answer: last option.

Step-by-step explanation:

According to the Product of powers property, you have:

$a^n*a^m=a^{(n+m)}$

As you can see, when you can add the exponents when you have powers with equal base.

Then, $6^5$ and $5^{-3}$ do not have the same base, therefore, the exponents can't be added.

Therefore, Eli is incorrect, because he added the exponents even though the bases are not the same.

6 0

4 years ago

In a batch of light bulbs, 30%are tinted, if 45 light bulbs are tinted,how many light bulbs are in the batch

soldier1979 [14.2K]

150 because 45/x=30/100 = 30x=4500 divide both by 30 and x=150

7 0

3 years ago

Please help, Brainliest if correct!!!

Lubov Fominskaja [6]

See the attached pic below

In the triangle formed by the statue and the boat, we have

$\tan23^\circ=\dfrac x{110+y}$

and

$\tan38^\circ50'=\dfrac xy$

We can solve either equation for $y$ , then substitute that into the other equation. First, let's abbreviate $t_1=\tan23^\circ$ and $t_2=\tan38^\circ50'$ . Then