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3 years ago

What information can be used to compare linear relationships? Explain why.

2 answers:

6 0

Answer: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.

Step-by-step explanation: Sample Response on Edge

kiruha [24]3 years ago

3 0

The slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).

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I need help with math hw what does x =

Pavlova-9 [17]

Answer:

x = 70

Step-by-step explanation:

The chord- chord angle x is half the sum of the arcs intercepted by the angle and its vertical angle, then

x = $\frac{1}{2}$ (80 + 60) = 0.5 × 140 = 70

4 0

3 years ago

A rancher purchased an SUV for $33,714 and made a down payment of 15% of the cost. The balance was financed for 4 years at an an

seropon [69]

Formula for monthly payment is:

A = P x (r(1+r)^t)/((1+r)^t-1) where P is the amount financed, r is the interest rate divided by 12 and t is the amount of time for the loan in months.

P = 33714 x 0.85 = 28656.90

A = 28656.90 x (0.07/12 (1+0.07/12)^48) / (1 +0.07/12)^48 - 1)

A = $686.23

3 0

3 years ago

If x+y=8 and xy=24, Fnd the value of x and y

Brilliant_brown [7]

Answer:

No solution

Step-by-step explanation:

I hope it helps

7 0

3 years ago

Read 2 more answers

Find the error in the following sample of work, if one exists.

ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

Line 1:

In line 1, the equation is given and is completely fine.

$y^{2}+8xy+2y+16x=0$

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

Line 2:

In line 2, the terms are grouped, from which we can factor out common terms.

$(y^{2}+8xy)+(2y+16x)=0$

This is also fine.

Line 3:

In line 3, the common term y is taken out from group 1 and 2 from other group.

$y(y+8x)+2(y+8x)=0$

which is exactly what is given in line 3.

Line 4:

In line 4 the common factors can be seen and easily split into 2 factors.

$(y+2)(y+8x)=0$

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0

3 years ago

8 - 4y + (-2y) + 5 What is this answer please tell me

Irina-Kira [14]

Answer:

13 - 6y

Step-by-step explanation:

8 - 4y + (-2y) + 5 = 13 - 6y

8 0

2 years ago

Read 2 more answers