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dexar [7]
1 year ago
13

8x2 +43x +30=0solve for x

Mathematics
1 answer:
storchak [24]1 year ago
8 0

Use the quadratic formula to find the values of x:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Where a, b and c are the coefficients of the quadratic equation.

\begin{gathered} x=\frac{-43\pm\sqrt[]{43^2-4\cdot8\cdot30}}{2\cdot8} \\ x=\frac{-43\pm\sqrt[]{1849-960}}{16} \\ x=\frac{-43\pm\sqrt[]{889}}{16} \end{gathered}

The equation has two solutions for x.

\begin{gathered} x1=\frac{-43+\sqrt[]{889}}{16} \\ x2=\frac{-43-\sqrt[]{889}}{16} \end{gathered}

As decimal numbers:

\begin{gathered} x1=-0.8239 \\ x2=-4.5510 \end{gathered}

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Answer:

Exercise 1:

base [b]=8cm

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hypotenuse [h]=?

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base [b]=6m

perpendicular [p]=bm

hypotenuse [h]=8m

By using Pythagoras law

h²=p²+b²

8²=b²+6²

b²=8²-6²

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Step-by-step explanation:

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Step-by-step explanation:

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