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kifflom [539]
3 years ago
9

The sphere's radius is half the radius of the hemisphere. How does the volume of this hemisphere compare with the volume of the

sphere?
Mathematics
2 answers:
Greeley [361]3 years ago
4 0
<span>A hemisphere is simply half a sphere, which means it has half of the volume of the original sphere. 


Put another way, the volume of the sphere is double the volume of the hemisphere. 

Therefore, the ratio of the volume of the sphere to the volume of the hemisphere is <span>2:1</span></span>
baherus [9]3 years ago
3 0

Answer:

The volume of the sphere is eight times the volume of hemisphere

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x-----> volume of the hemisphere

y-----> volume of the sphere

z^{3}=\frac{x}{y}

in this problem we have

z=\frac{1}{2}

substitute

(\frac{1}{2})^{3}=\frac{x}{y}

(\frac{1}{8})=\frac{x}{y}

y=8x

that means------> The volume of the sphere is eight times the volume of hemisphere

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If the perimeter of a rectangle is 360 feet, and the length is twice the width, what is the length?
geniusboy [140]

Answer:

(P) =360

(l) =?

(b) =?

so, let the breadth be x

let the length be 2x

Perimeter of rectangle=2(l+b)

360 =2(2x+x)

360/2 =2x

180/2 =x

60 =x

x =60

ATQ

Breadth = 60

length= 60 ×2

=180

8 0
3 years ago
I was confuse on number 5, 6, 7, 8.
KiRa [710]

Answer:

5. 3/5-2/5=1/5; answer is 1/5

6.7/10-3/10=4/10; answer is 2/5(simplify)

7.5/6-4/6=1/6; answer is 1/6

8.3/4-2/4=1/4; answer is 1/4

Step-by-step explanation:

Explanation is above, when subtracting fractions remember that the denominator must be the same and you can subtract the numerator.

Hope this helps!

5 0
2 years ago
Read 2 more answers
Find the critical points, domain endpoints, and local extreme values for the function
aliina [53]

Answer:

a) x = -3, b) x = 0, x = -6, c) x = 0, d) x = -6

Step-by-step explanation:

a) Let derive the function:

f'(x) = \frac{10\cdot x \cdot (x+3)-5\cdot x^{2}}{25\cdot (x+3)^{2}}

f'(x) is undefined when denominator equates to zero. The critical point is:

x = -3

b) f'(x) = 0 when numerator equates to zero. That is:

10\cdot x \cdot (x+3) - 5\cdot x^{2} = 0

10\cdot x^{2}+30\cdot x -5\cdot x^{2} = 0

5\cdot x^{2} + 30\cdot x = 0

5\cdot x \cdot (x+6) = 0

This equation shows two critical points:

x = 0, x = -6

c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that x = 0 corresponds to a local maximum. (See Attachment)

d) By plotting the function, it is evident that x = -6 corresponds to a local minimum. (See Attachment)

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3 years ago
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3 years ago
Consider the graph of the quadratic function. Which interval on the x-axis has a negative rate of change?
Gre4nikov [31]

The average rate of change is defined as:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

For AVR to be negative, it must comply with:

x2 - x1> 0

f (x2)

Therefore, we observe that the interval that fulfills these conditions is the whole interval to the right of the parabola.

Among the options given, this interval is:

1 to 2.5

Answer:

An interval on the x-axis that has a negative rate of change is:

D. 1 to 2.5

3 0
3 years ago
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