(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
Answer:
Maximize C =


and x ≥ 0, y ≥ 0
Plot the lines on graph




So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)
Substitute the points in Maximize C
At (0,1.7)
Maximize C =
Maximize C =
At (2.125,0)
Maximize C =
Maximize C =
At (0,0)
Maximize C =
Maximize C =
So, Maximum value is attained at (2.125,0)
So, the optimal value of x is 2.125
The optimal value of y is 0
The maximum value of the objective function is 19.125
Answer:
Assuming the numerator was 1.

Step-by-step explanation:
Assuming the numerator was 1.

Answer:
How long did she work for though?
Step-by-step explanation:
Answer:
The answer is C
Step-by-step explanation:
Let's solve your equation step-by-step.
4(x−2)=6x+18
Step 1: Simplify both sides of the equation.
4(x−2)=6x+18
(4)(x)+(4)(−2)=6x+18(Distribute)
4x+−8=6x+18
4x−8=6x+18
Step 2: Subtract 6x from both sides.
4x−8−6x=6x+18−6x
−2x−8=18
Step 3: Add 8 to both sides.
−2x−8+8=18+8
−2x=26
Step 4: Divide both sides by -2.
−2x/−2=26/−2
x=−13
Answer:
x=−13