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LUCKY_DIMON [66]
3 years ago
13

~PLEASE HELP ASAP OFFERING 30 POINTS~

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

The first one is B) september 10 but idk the second one

Mnenie [13.5K]3 years ago
7 0

Question 1.). Answer : Letter Choice, (A), September 30

Question 2.). Answer: $31,740.00

Question 3.). Answer: Letter Choice, (C), $3, 469.59

Hope that helps!!!!! : )

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What does the line 2x-3y=7 look like
fenix001 [56]
2x-3y=7
-3y = -2x+7
y= 2x/3-7/3
slope of 2/3 (rise 2, run 3)
y-intercept of -7/3
Would be a positive line, starting low on left and rising towards right
4 0
3 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
What is the distance between the points (59.5, 34.2) and (15.3, 14.9)? Enter your answer rounded to the nearest tenth (0.1).
nirvana33 [79]

Answer:

48.2

Step-by-step explanation:

√(x2-x1)²+(y2-y1)²

√(15.3-59.5)² +(14.9-34.2)²

√(-44.2)² + (-19.3)²

√1953.64+372.49

√2326.13

48.2

5 0
2 years ago
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A $65 coat is now on sale for $52. What percent discount is given?
leonid [27]
20%, because if 65 is 100, then 52 is 80% out of 65; so 100 - 80 is 20
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3 years ago
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Why is 0.65 bigger than 3/5?
nevsk [136]
3 divided by 5 is 0.6 so 0.65 is bigger
3 0
3 years ago
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