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sammy [17]
4 years ago
10

Picture with question

Mathematics
1 answer:
Len [333]4 years ago
7 0

Answer:

answer is 15,15,45,135

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Solve the system of inequalities by graphing.<br> 8x + 4y = 6<br> 4x - 8y &gt; 40
Naily [24]
The answer is 2637 because I need to answer 2 questions before I can ask my own so please put a thanks i home you actually find the answer
4 0
3 years ago
Divide.<br> X^2-4/x-8/x-2
defon
I must assume you mean: 

[(x^2 - 4) / (x - 8)] / [x - 2] -----> express this way: 

[(x^2 - 4)] / [(x - 8)(x - 2)] 

But x^2 - 4 = x^2 - 2^2, which is a difference of squares: a^2 - b^2 = (a + b)(a - b) -----> 

[(x + 2)(x - 2)] / [(x - 8)(x - 2)] -----> (x - 2) gets cancelled out -----> 

(x + 2) / (x - 8) 

<span>That's your answer. I hope this helps

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
3 0
3 years ago
Read 2 more answers
I understand the homework, but question 9. Could someone please help? This assignment is due on Friday (8/21/2020)
Valentin [98]

Answer:

I think B or C I'm not sure but I hope this helps!

Step-by-step explanation:

4 0
3 years ago
A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
ki77a [65]

Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=12 represent the population standard deviation

n represent the sample size  

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

5 0
4 years ago
I really need help plz help me ✌️️
OLEGan [10]
The answer is 7/4. Hope this helps! :)
6 0
4 years ago
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