The answer is; The frequency for allele O = 0.7746 while that of o = 0.2254
Well use the hardy Weinberg equation of a population at equilibrium; p2 + 2pq + q2 = 1
In our case, p2 will be 60/100 = 0.6; therefore p = square-root of 0.6 = 0.7746
Remember also that the frequencies of alleles of the same gene add up to one (1); i.e p + q = 1
Therefore q = 1 – 0.7746 = 0.2254
Water molecules have a polar bond.
Answer:
0% (none)
Explanation:
The female drosophila is heterozygous for X-linked recessive mutation. An X-linked recessive mutation is expressed in females only when present in the homozygous state. Therefore, the female progeny should have two copies of the mutant allele to express this mutation. Let's suppose that the genotype of the heterozygous female is X^cX and that of the male is XY. The cross would obtain progeny in following ratio=
X^cX x XY= 1/4 X^cX: 1/4 XX: 1/4 X^cY: 1/4 XY
Since none of the female progeny is homozygous recessive (X^cX^c), the cross would not obtain any female progeny expressing the X-linked recessive mutation.
Somatic cell chromosomes (body cells) are in pairs. if you mean 12 chromosomes,Then there will be 6 pairs, groups of two, chromosomes. The gamete (aka sex cell) will thus contain 6 chromosomes.
One chromosome from each pair ends up in one gamete, normally.
