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jok3333 [9.3K]
3 years ago
10

In a genetic cross, where the male parent is heterozygous for curly hair (Hh) and the female parent is homozygous for straight h

air (hh), the offspring would ....
a. all have straight hair
b. all have curly hair
c. half would have straight hair and half curly hair
d. a random mixture of straight and curly haired offspring, with more having curly hair.
Biology
1 answer:
svet-max [94.6K]3 years ago
3 0
                    H                h
h              Hh               hh
h              Hh               hh

In a genetic cross, <span>where the male parent is heterozygous for curly hair (Hh) and the female parent is homozygous for straight hair (hh), </span>the offspring would C. HALF WOULD HAVE STRAIGHT HAIR AND HALF CURLY HAIR.

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In Labrador dogs, black coat is dominant to chocolate, normal vision is dominant to progressive retinal atrophy (PRA), and normal hip joint is dominant to hip dysplasia. All these genes assort independently. Two dogs that are heterozygous for alleles of all three genes are crossed. Using rules of probability (not a Punnett square), what is the chance that the first pup born to these dogs will be chocolate, have normal vision, and have normal hip joints?

BbVvHh x BbVvHh= BBVVHH, BbVvHh, BbVvHh, bbvvhh

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probability of having a first born of these dogs will be chocolate, have normal vision and have normal hip joint is 0

Explanation:

As the punette square gives 3:1 phenotype having three black coat, normal vision and normal hip joint and one chocolate, progressive retina altropy and hip dysplasia

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