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3 years ago

I need an equation for segment XY is unequal to segment AC!

Mathematics

1 answer:

AysviL [449]3 years ago

7 0

Segment xy\neq segment ac

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Find the distance round to the nearest tenth (-8, -6) (-3,-2)

lina2011 [118]

Answer:

$\displaystyle d \approx 6.4$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-8, -6)

Point (-3, -2)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-3+8)^2+(-2+6)^2}$
[√Radical] (Parenthesis) Add: $\displaystyle d = \sqrt{(5)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{25+16}$
[√Radical] Add: $\displaystyle d = \sqrt{41}$
[√Radical] Evaluate: $\displaystyle d = 6.40312$
Round: $\displaystyle d \approx 6.4$

7 0

2 years ago

Read 2 more answers

A car speeds up from 20 m/s to 50 m/s over a time of 10 seconds. What is the cars acceleration

wlad13 [49]

Answer:

3 m/s

Step-by-step explanation:

$\frac{50 - 20}{10} = 3$

8 0

3 years ago

Please help me i will give brainlist to the correct answer

mestny [16]

Answer:

<ABC = 27

< BAC = 126

Step-by-step explanation:

<C = <B since it is an isosceles triangle. We know this since AC - AB

<C = 27 so <ABC = 27

The sum of the angles of a triangle = 180

A + B+ C = 180

A + 27+27 = 180

A + 54 =180

A = 180-54

A =126

< BAC = 126

5 0

3 years ago

What is the value of (-7 + 3i) - (2-6i)?

BigorU [14]

First you must distribute the minus sign to the number bolded bellow:

(-7 + 3i) - (2 - 6i)

(-7 + 3i) + (-2 + 6i)

-7 + 3i - 2 + 6i

Now you must combine like terms. Imaginary numbers can only combine with imaginary and real number can only be combined with real numbers:

(-7 + (-2) ) + (3i + 6i)

-9 + 9i

I hope this helped! Let me know if you have any questions :)

~ Just a girl in love with Shawn Mendes

4 0

3 years ago

Rewrite the expression as a single logarithm and simplify the result. ln lcosxl +lnltanxl

NNADVOKAT [17]

Recall your logarithms rules

$\bf ln|cos(x)|+ln|tan(x)|\\\\
-----------------------------\\\\
log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)\qquad thus\\\\
-----------------------------\\\\
ln|cos(x)tan(x)|\implies ln\left| cos(x)\cdot \cfrac{sin(x)}{cos(x)} \right|\implies 
ln|sin(x)|$

6 0

3 years ago