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klemol [59]
3 years ago
9

"Calculate the value of b in the triangle below." HELP PLZ WILL GIVE BRAINLIEST

Mathematics
1 answer:
Viktor [21]3 years ago
8 0

Answer:

b { }^{2}  = (61m) {}^{2}  - (11m) {}^{2}

b {}^{2}  = 3721 - 121

b {}^{2}  = 3600

\sqrt{b {}^{2} }  =  \sqrt{3600}

b = 60

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Answer:

165.2

Step-by-step explanation:

7%x4=28

28 percent of 590 = <u>165.2</u>

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A cube has a volume of 64 cubic units. What is its surface area
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Two linear functions are shown.
sasho [114]

Answer:

Function A has a greater initial value because the initial value for Function A is 6 and the initial vale for Function B is 3

Step-by-step explanation:

The data for Function A is presented here as follows;

\begin{array}{cc}x&y\\-1&9\\0&6\\1&3\\2&0\end{array}

The slope of the function, 'm', is given using any two points as follows;

m = (9 - 3)/((-1) - 1) = -3

The slope of the function = -3

The equation of function in point and slope form is given as follows;

y - 3 = -3·(x - 1)

The equation of Function A, is therefore, given as follows;

y = 3 - 3·x + 3 = 6 - 3·x

∴ y = 6 - 3·x

The equation of Function B is given as follows;

y = 6·x + 3

The initial value of a function is given by the y-intercept of the function, where the input variable (x-variable) is zero

The initial value, (y-intercept) of Function A, f(0) is therefore found as follows;

f(x) = y = 6 - 3·x

f(0) = 6 - 3×0 = 6

The initial value of Function A, f(0) = 6

Similarly, the initial value, (y-intercept) of Function B, f(0) is found as follows;

f(x) = y = 6·x + 3

f(0) = 6×0 + 3 = 3

The initial value of the Function B, f(0) = 3

Therefore, we have that Function A has a greater initial value than Function B

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3 years ago
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Answer: {y/y>-4}

Step-by-step explanation:

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