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4 years ago

Which Step should be performed to isolate X

1 answer:

7 0

If you're talking x in particular, it can't be isolated. See, if we have this equation, x=5, we divide the Answer by the Answer, so 5/5=1. We divide the Answer by x, so x would appear x/5. So, x/5=1

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I NEED HELP PLS I FORGOT HOW TO DO THIS HELP

KengaRu [80]

Answer:

Step-by-step explanation:

how many shapes of size A are in B ?

I counted 9.5

then just multiply the count * the size of A

got it?

7 0

3 years ago

Read 2 more answers

Please help if you can!

Sloan [31]

2340 is a rational number because you can divide by it.
<span>3π is an irrational number because you cannot divide by it. </span>

8 0

4 years ago

Read 2 more answers

R=1/6 the problem is 3r2

kogti [31]

Step-by-step explanation:

Putting the value of r

3 ( 1/6) 2

So 3 × (1/6) = 0.5 × 2 = 1

7 0

4 years ago

A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

$P = P_{1} + P_{2} + P_{3}$

$P_{1}$ is the probability that all three of them are 13-watt. So:

$P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277$

$P_{2}$ is the probability that all three of them are 18-watt. So:

$P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415$

$P_{3}$ is the probability that all three of them are 23-watt. So:

$P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173$

$P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865$

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

$P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245$

There is a 12.45% probability that one bulb of each type is selected.

3 0

3 years ago

Sofia cuts a piece of felt in the shape of a kite for an art project. The top two sides measure 20 cm each and the bottom two si

dolphi86 [110]

In geometry, it is always advantageous to draw a diagram from the given information in order to visualize the problem in the context of the given.

A figure has been drawn to define the vertices and intersections.

The given lengths are also noted.

From the properties of a kite, the diagonals intersect at right angles, resulting in four right triangles.

Since we know two of the sides of each of the right triangles, we can calculate their heights which in turn are the segments which make up the other diagonal.

From triangle A F G, we use Pythagoras theorem to find

h1=A F=sqrt(20*20-12*12)=sqrt(256)=16

From triangle DFG, we use Pythagoras theorem to find

h2=DF=sqrt(13*13-12*12)=sqrt(25) = 5

So the length of the other diagonal equals 16+5=21 cm

5 0

3 years ago