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3 years ago

7

A guy-wire extends from the top of a cell phone tower to a point on the ground that is 25 ft from the base of the tower. What is

the approximate length of the guy-wire if the height of the cell phone tower is 75 ft?

1 answer:

qaws [65]3 years ago

6 0

Answer:

79.1 ft. I just took the test and got it correct. (:

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If f(x)=-x+2 find f(6)

marshall27 [118]

Answer:

Answer: -4

Step-by-step explanation:

${ \rm{f(x) = - x + 2}} \\ \\ { \rm{f(6) = - (6) + 2}} \\ \\ { \rm{f(6) = - 4}}$

7 0

2 years ago

Read 2 more answers

solniwko [45]

recall that the radius is the distance from the center of a circle to any point on the circle.

we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad
(\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{radius}{r}=\sqrt{[-8-(-16)]^2+[-8-(-14)]^2}
\\\\\\
r=\sqrt{(-8+16)^2+(-8+14)^2}\implies r=\sqrt{8^2+6^2}
\\\\\\
r=\sqrt{100}\implies \boxed{r=10}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \textit{equation of a circle}\\\\
(x- h)^2+(y- k)^2= r^2
\qquad
center~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquad
radius=\stackrel{10}{ r}
\\\\\\\
[x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft$

5 0

3 years ago

Please solve with explanation

Bas_tet [7]

Answer:

I don't know

Explanation:

Sorry :(

4 0

3 years ago

Rename 1 3/4 as an improper fraction.

fiasKO [112]

Answer:

7/4

Step-by-step explanation:

1 3/4=1 x 4=4 + 3=7/4

8 0

3 years ago

Estimate the difference. 9 1/2- 1 6/7

Sav [38]

Answer:

$= 7 \frac{9}{14} \\$

Step-by-step explanation:

$9 \frac{1}{2} - 1 \frac{6}{7} \\ \frac{19}{2} - \frac{13}{7} \\ \frac{133 - 26}{14} \\ = \frac{107}{14} \\ = 7 \frac{9}{14}$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

4 years ago