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3 years ago

PLEASE HELP!! I got until monday to finish this!!

Mathematics

2 answers:

uysha [10]3 years ago

6 0

Bc and gh respectively

erica [24]3 years ago

5 0

1.would be AEH.
2.would be ADH.

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Please help! Thank you so much.

inysia [295]

Answer:

4 over 5

Step-by-step explanation:

its 4 over 5 because your going to get a decimal and the other answers you will get a integer which the question isnt asking for so the answer is 4 over 5

4 0

4 years ago

322/14 .....plzzzzzzzzzzzzzzzzzzzzzzz

DIA [1.3K]

23 is the answer 322 divided by 14 is 23

3 0

3 years ago

Read 2 more answers

What is the area of this parallelogram? ___ sq in

ikadub [295]

A=BH

Area=Base*Height

The base is 7 in+6 in which equals 13 inches.

Now were set, 13*45.5

Solve to get the answer 591.5

-Seth

4 0

3 years ago

Read 2 more answers

The product of 5 and a number is at least 20.

svp [43]

Answer:

Step-by-step explanation:

the answer is 5x $\geq$ 20

8 0

3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago