Answer:
x = 4√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is one leg
- b is another leg
- c is hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
a = 19
b = <em>x</em>
c = 21
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 19² + x² = 21²
- Isolate <em>x</em> term: x² = 21² - 19²
- Exponents: x² = 441 - 361
- Subtract: x² = 80
- Isolate <em>x</em>: x = √80
- Simplify: x = 4√5
X will equal 12, and y will equal 18.
Answer:
2406.17 cm³
Step-by-step explanation:
The following data were obtained from the question:
Height (h) = 24.4 cm
Base length (L) = 17.2 cm
Volume (V) =?
Next, we shall determine the base area of the pyramid. This can be obtained as follow:
Base length (L) = 17.2 cm
Base area (B) =.?
B = L × L
B = 17.2 × 17.2
B = 295.84 cm²
Finally, we shall determine the volume of the pyramid. This can be obtained as follow:
Height (h) = 24.4 cm
Base area (B) = 295.84 cm²
Volume (V) =?
V = ⅓Bh
V = ⅓ × 295.84 × 24.4
V = 2406.17 cm³
Thus, we volume of the pyramid is 2406.17 cm³
A is not true :) Hope i helped!
<span>Simplifying
0x + 7 + 5x = 2x + 30 + 40
Anything times zero is zero.
0x + 7 + 5x = 2x + 30 + 40
Combine like terms: 0 + 7 = 7
7 + 5x = 2x + 30 + 40
Reorder the terms:
7 + 5x = 30 + 40 + 2x
Combine like terms: 30 + 40 = 70
7 + 5x = 70 + 2x
Solving
7 + 5x = 70 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
7 + 5x + -2x = 70 + 2x + -2x
Combine like terms: 5x + -2x = 3x
7 + 3x = 70 + 2x + -2x
Combine like terms: 2x + -2x = 0
7 + 3x = 70 + 0
7 + 3x = 70
Add '-7' to each side of the equation.
7 + -7 + 3x = 70 + -7
Combine like terms: 7 + -7 = 0
0 + 3x = 70 + -7
3x = 70 + -7
Combine like terms: 70 + -7 = 63
3x = 63
Divide each side by '3'.
x = 21
Simplifying
x = 21</span>