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3 years ago

15

What is the geometric sequence of 1/32, 1/8, 1/2, 2, 8

2 answers:

crimeas [40]3 years ago

6 0

The geometric sequence is multiplied by 4

erastovalidia [21]3 years ago

5 0

The formula for the nth term of a sequence with first term a1 and common ratio r is
an=a1(r)^(n-1)
r=a(n+1)/an

to find the common ratio, divide a term by the previous term
8/2=4
2/(1/2)=4
(1/2)/(1/8)=4
(1/8)/(1/32)=4
common ratio is 4
first erm is 1/32

an=(1/32)(4)^(n-1)

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1 year ago

Determine the slope of the line passing through (-8,-5) and (-10,-9)

nikklg [1K]

Answer:

2

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

The federal government requires a car manufacturer to have a minimum miles per gallon (mpg) average over the models it makes. Su

valentinak56 [21]

Answer:

25 mpg

Step-by-step explanation:

We have a set of values 19, 21, 22, 28 and 18

The average (which is the mean of the set of values ) is :

19 + 21 + 22 + 28 + 18 = 21.6 mpg out of the government requirement

So we need a value such as the mean become at least 25 mpg

We have to solve the equation:

(19+21+22+28+ x)/ 5 = 25

(90 + x ) /5 = 25 ⇒ 90 + x = 125 ⇒ x = 35 mpg

If we get the mean of the set of values including 35 we have:

(19 +21+ 22+ 28 + 35 ) / 5 = 25 mpg government requirement

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3 years ago

What is an appropriate data display for the distribution of teachers by age?

sertanlavr [38]

Not really sure what exactly you are asking, but maybe a bar graph?

4 0

3 years ago

Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.

Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

(3,4)

(4,-6)

The distance 'd' between (3,4) and (4,-6)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):$

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substituting the points values

$=\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}$

$=\sqrt{1+10^2}$

$=\sqrt{1+100}$

$=\sqrt{101}$

$=10.0$ units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0

3 years ago