Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Three heads.
- Event B: Fair coin.
The probability associated with 3 heads are:
out of 0.5(fair coin).- 1 out of 0.5(biased).
Hence:

The probability of 3 heads and the fair coin is:

Then, the conditional probability is:

0.1 = 10% probability that the chosen coin was the fair coin.
A similar problem is given at brainly.com/question/14398287
Answer: the nots confused me y’ is that integral or what
Step-by-step explanation:
Sine = (opposite)/(hypotenuse).
Cosine = (adjacent)/(hypotenuse).
Tangent = (opposite)/(adjacent).
Fill in the numbers. They're all on the drawing . Then memorize these definitions. You'll need them as long as you're in school, and possibly after.
Eight below zero would express the value -8, negative eight,
but not 8.