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2 years ago

This equation x (x2 - 1) y"+ (1- x?) y' +9(2x - 2)y has a regular singular points at x =

Mathematics

1 answer:

KiRa [710]2 years ago

4 0

Answer: the nots confused me y’ is that integral or what

Step-by-step explanation:

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If f, g, h

ale4655 [162]

Answer:

F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(3) = 3(3)^2 + 1 = 27 + 1 = 28

G(4) = 2(4) - 3 = 8 - 3 = 5

2H(5) = 2(5) = 10

F(3) + G(4) - 2H(5) = 28 + 5 - 10

F(3) + G(4) - 2H(5) = 23

Step-by-step explanation:

I believe I'm not sure tho

6 0

3 years ago

Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles. Write an inequality that shows the distance johnathan

Mekhanik [1.2K]

An inequality that shows the distance Johnathan could of ran any day this week is:

$x\leq 3.5$

Solution:

Let "x" be the distance Johnathan can run any day of this week

Given that,

Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles

Therefore,

Number of days ran = 5

The most he ran in 1 day = 3.5 miles

Thus, the maximum distance he ran in a week is given as:

$distance = 5 \times 3.5 = 17.5$

The maximum distance he ran in a week is 17.5 miles

If we let x be the distance he can run any day of this week then, we get a inequality as:

$x\leq 3.5$

If we let y be the total distance he can travel in a week then, we may express it as,

$y\leq 17.5$

8 0

2 years ago

Locate the absolute extrema of the function on the closed interval: y = 3x^(2/3) - 2x, [-1, 1]

Alecsey [184]

To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).

7 0

3 years ago

7/2x + 1/2x + 5 1/2 + 92x the value of x is..

jeka94

I'm not entirely sure what you mean but simplifying this expression results in 96x + 5 1/2.

8 0

2 years ago

Answer 6s^5t x s^4t^2

babunello [35]

Answer:

6s⁹t³

Step-by-step explanation:

6s⁵t ₓ s⁴t² =

= 6ₓs⁵⁺⁴t¹⁺²

= 6s⁹t³

8 0

2 years ago

Read 2 more answers

This equation x (x2 - 1) y"+ (1- x?) y' +9(2x - 2)y has a regular singular points at x =​

This equation x (x2 - 1) y"+ (1- x?) y' +9(2x - 2)y has a regular singular points at x =