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juin [17]
3 years ago
5

Units of Length

Mathematics
1 answer:
grin007 [14]3 years ago
7 0

the answer is:

78.7 (i rounded it to the nearest tenth)

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Y/9+5=0<br> solve equation
Alecsey [184]
 You said                                   y/9  +  5  =  0

Subtract 5 from each side:      y/9           = -  5

Multiply each side by 9 :          y              =  -45
4 0
3 years ago
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Venessa has a piggy bank that contains a collection of nickels, pennies, dimes and quarters. She randomly draws a coin out of th
Tamiku [17]

Answer:

58

Step-by-step explanation:

Coins Number of Drawsnickel 32penny 54dime 13quarter 29Total Number of Draws = 32 + 54  + 13 + 29 = 128Probability of Quarter drawn = 29/128the number of times a quarter would be drawn if Venessa draws a coin 256 times  = (29/128)  * 256= 29 *2= 58 option B is the right answer

3 0
3 years ago
Serious I need your help plz
makkiz [27]
Greetings!

Solve for x.
\frac{x+11}{8} =-3
Multply both sides by 8 to get rid of the fraction.
8(\frac{x+11}{8}) =8(-3)
x+11=-24
Add -11 to both sides.
(x+11)+(-11)=(-24)+(-11)
The Answer Is:
x=-35

Hope this helps.
-Benjamin
3 0
4 years ago
Help IS THE ANSWER A OR C?????????
Neko [114]
I am not really sure but it might be A
3 0
4 years ago
Lucy wants to wear different clothes everyday. She has 8 dresses, 7 pairs of shoes, and 3 pairs of earrings. Lucy can choose 1 d
elena-14-01-66 [18.8K]

She can wear outfits differently in 167 days.

Given that Lucy wants to wear different clothes everyday, and she has 8 dresses, 7 pairs of shoes, and 3 pairs of earrings, and Lucy can choose 1 dress, 1 pair of shoes, and 1 pair of earrings every day, but however 1 dress and 1 pair of shoes don't look good together, to determine, in such circumstances, how many days can she wear outfits differently, the following calculation must be made:

  • (8 x 7 x 3) - 1 = X
  • 168 - 1 = X
  • 167 = X

Therefore, she can wear outfits differently in 167 days.

Learn more about maths in brainly.com/question/17002975

3 0
3 years ago
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