All categories

3 years ago

How many times can 9 go into 82

Mathematics

1 answer:

Assoli18 [71]3 years ago

3 0

The answer is 9.1.

You might be interested in

Give EG = 5x+7 EF =5x and FG=2x-7

Len [333]

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

EG = 5x+7
EF = 5x
FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

5x + 7 = 5x + 2x - 7
2x = 14
x = 7

Then

EG = 5*7 + 7 = 42
EF = 5*7 = 35
FG = 2*7 - 7 = 7

7 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

3 years ago

Please help

Maurinko [17]

Answer:

704 square yards

Step-by-step explanation:

10 * 19 = 190

190 * 2 = 380

12 * 19 = 228

12 / 2 = 6

6 * 8 = 48

48 * 2 = 96

96 + 228 + 380 = 704

Hope this helped! Have a nice day, and plz mark as brainliest if correct!!!

-Lil G

7 0

3 years ago

Read 2 more answers

How do you write 12 ten thousands, 8 thousands, 14 hundreds, 7 ones in standard form

kap26 [50]

128,147 that is in standard form

6 0

3 years ago

beks73 [17]

Answer:

bhbhhbhjb

Step-by-step explanation:

4 0

3 years ago