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9966 [12]
4 years ago
11

Solve for b. -1/6b=3

Mathematics
1 answer:
zhannawk [14.2K]4 years ago
3 0

Answer:

b = -18

Step-by-step explanation:

-1/6b=3

Multiply each side by -6

-6*-1/6b=3(-6)

b = -18

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Find the absolute maximum and minimum of the function on the given domain. f (x comma y )equals 8 x squared plus 7 y squared on
pickupchik [31]

Answer:

the maximum value is 7

The minimum value is 0

Step-by-step explanation:

Step One : Interpret the question

       The above question can be written like

The Equation

            f(x,y) = 8x^2 +7y^2

The diagram of the triangular plate and the bounded lines is shown on the first uploaded image

          From the diagram  f(0,0) = 8(0)^2 +7(0)^2 =0

                                          f(1,0) =8(1)^2 + 7(0)^2 = 8

                                          f(0,1) =8(0)^2 + 7(1)^2 = 7

Partial differentiation of the equation w.r.x

                           A =\frac{\delta f}{\delta x }  = 16x

 Partial differentiation of the equation w.r.y

                          B =\frac{\delta f}{\delta y }  = 14y            

Looking at the diagram the maximum value is 7 i.e  at (x , y) = (0,1)

The minimum value is 0 i.e  (x , y) = (0,0)

3 0
3 years ago
Is it possible to have a triangle with two right angles? Explain your reasoning.
Black_prince [1.1K]

Answer and Explanation:

Because of the fact that the sum of the three interior angles of a triangle must be 180 degrees, a triangle could not have two right angles.

6 0
4 years ago
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I need advice!
g100num [7]
Alright, so you can try to study hard and gain a passing grade (A+) for the other two quarters. 
4 0
4 years ago
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The probability of drawing two red candies without replacement is 1335 , and the probability of drawing one red candy is 25 . Wh
FrozenT [24]

Answer:

13/14 I think

Step-by-step explanation:


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4 years ago
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Artyom0805 [142]

Answer:

∠7 = 81°

Step-by-step explanation:

∠1 = ∠7

3x + 18 = 2x + 39

3x - 2x = 39 - 18

x = 21

∠7 = 2x + 39

∠7 = 2(21) + 39

∠7 = 42 + 39

∠7 = 81°

5 0
3 years ago
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