Given 2x - y = 6, solve for y

Estimate 12.56+12.69 using front-end estimation.

marissa [1.9K]

<span>12.56+12.69 = 12.60 + 12.70 = 25.30

answer

</span><span>A. about $25.30</span>

5 0

4 years ago

Jayden’s new puppy weighed 11 1/4 pounds at 4 weeks old. At 16 weeks old, the puppy weighed 1 2/3 times more.

musickatia [10]

Answer:

18.75 or 18 3/4 lbs

Step-by-step explanation:

We just have to multiply 11 1/4 and 1 2/3 to get the product, 18.75 or 18 3/4.

First we have to translate our fractions into decimals:

11.25 (11 1/4) and 1.166667 (1 2/3)

multiply:

11.25 x 1.166667 = 18.75

convert back to fraction:

18 3/4

Hope This helps! Good Luck! If you have any questions please ask me, I would me more than happy to help you understand this method. If you are doing it a different way, I can help with that too.

5 0

3 years ago

You have two disks. The bigger one has 24 inch radius and its is rigidly attached to a peg (it doesn’t turn or move). The smalle

Zanzabum

Perimeter of bigger disc = 2π*24 inch
perimeter of bigger disc = 2π*8 inch

number of rotations =2π*24/2π*8 = 3

4 0

3 years ago

A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new

stiv31 [10]

Answer:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

$\hat p=\frac{135}{500}=0.27$ estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

$p_o=0.2$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0

4 years ago

Help me with this math problem

Rama09 [41]

Answer:

Step-by-step explanation:

8 0

3 years ago