There are 3
exclusive mutually birth orders that could
make two
affecteds and 1 unaffected - unaffected child first born, unaffected child
second born,
and unaffected child third born. Thus, there is a 3/64 + 3/64 + 3/64
= 9/64
chance that 2 out of 3 children will be affected.
Answer:
ok help you with what? I got you if u give me brainliest
Explanation:
Ksksksksskksksksksksksksksksksksks
The answer is................................................C
Answer:
C) presence of hazardous radioactive materials
Explanation:
<u>radioactive- emitting or relating to the emission of ionizing radiation or particles.</u>
<h2><em>
hint the warning </em>
∨</h2><h2>
∨</h2><h2>
</h2><h2>
</h2>