Step-by-step explanation:
2
hope it helps.
thank you
136 should be your answer
Answer:
In the explanation
Step-by-step explanation:
Going to start with the sum identities
sin(x+y)=sin(x)cos(y)+sin(y)cos(x)
cos(x+y)=cos(x)cos(y)-sin(x)sin(y)
sin(x)cos(x+y)=sin(x)cos(x)cos(y)-sin(x)sin(x)sin(y)
cos(x)sin(x+y)=cos(x)sin(x)cos(y)+cos(x)sin(y)cos(x)
Now we are going to take the line there and subtract the line before it from it.
I do also notice that column 1 have cos(y)cos(x)sin(x) in common while column 2 has sin(y) in common.
cos(x)sin(x+y)-sin(x)cos(x+y)
=0+sin(y)[cos^2(x)+sin^2(x)]
=sin(y)(1)
=sin(y)
For this question I would put the problem into slope-intercept form or y=mx+b. So add 3x to both sides so that the equation becomes y=3x+3 Then this equation is easier to graph. the y-intercept is 3 so there is a point at (0,3). and the slope is 3 so you would go over 1 up 3. Then connect those points and you have finished the graph. Hope this helps.
