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sergiy2304 [10]
4 years ago
6

Jason is working in his garden. The garden is triangular. The length of the longest side is 10 feet. He uses a portion of the ga

rden for herbs. The portion is a similar triangle whose longest side is 4 feet. What is the percentage of the area of the herb garden compared to the area of the entire garden?
Mathematics
1 answer:
miss Akunina [59]4 years ago
5 0
To get the percentage of area we shall proceed as follows:
linear scale factor =length of herb/ length of garden
=4/10
but
area scale factor=(linear scale factor)^2
area scale factor=(2/5)^2=4/25
thus the percentage area proportion will be:
4/25*100
=16%
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George bought 7 ounces of grapes for $3.36. What was the price of the grapes per<br> ounce?
White raven [17]

Your answer is quite simple, really. All you have to do is divide $3.36 by 7 (The ounces of grapes he bought), and your answer should come out to be $.48, to check if this is correct, you then should add .48, 7 times, or multiply it by 7. Which, is what I did. And that should bring you to 3.36!

8 0
3 years ago
State whether the given measurements determine zero, one, or two triangles.. . C = 30°, a = 32, c = 16
Nat2105 [25]
Sin(A) / a = Sin(C)/c
Sin(A) = a * Sin(C)/c
Sin(A) = 32 * Sin(30)/16
Sin(A) = 32 * 0.03125
Sin(A) = 1

A = 90° 

<span>By the law of sines, angle A must be 90 degrees. That makes side a the hypotenuse of a 30-60-90 triangle. There is only one triangle. The third side is 16</span>√<span>3, and the third angle 60</span>°<span>.</span>
6 0
3 years ago
The axis of symmetry for a quadratic equation can be found using the formula x =-b/2a , where a and b are coefficients in the qu
Liula [17]
If x = -b/2a, then 2a = -b / x so a = -b / 2x or a = b / -2x

So the denominator is -2x because it has to take the minus sign that the numerator refused to take ;-)
4 0
4 years ago
Read 2 more answers
13^-11x13^16x13^-3x13^^4x13^-5
stiv31 [10]
Since the bases are all 13, keep the base and add the powers.
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4 0
4 years ago
Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1
GalinKa [24]

Answer:

-2,\ -1,\ -\dfrac{1}{2},\ 3.

Step-by-step explanation:

Consider polynomial 2x^4+x^3-14x^2-19x-6.

If x=-2 is its zero, then you can divide the polynomial 2x^4+x^3-14x^2-19x-6 by x+2 and get

2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).

If x=-1, then the polynomial 2x^4+x^3-14x^2-19x-6 can be rewritten as

2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).

The quadratic polynomial has roots

x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.

Then the polynomial 2x^4+x^3-14x^2-19x-6 has zeros -2,\ -1,\ -\dfrac{1}{2},\ 3.



7 0
3 years ago
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