Which is the graph of g(x) = 2
1 answer:
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Answer:
Step-by-step explanation:
We can solve this multiplication of polynomials by understanding how to multiply these large terms.
To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.
- <em>We can do this by focusing on one term in the first polynomial and multiplying it by </em><em>all the terms</em><em> in the second polynomial. We'd then repeat this for the remaining terms in the second polynomial.</em>
Let's first start by multiplying the first term of the first polynomial, , by all of the terms in the second polynomial. (
)
Now, we can add up all these expressions to get the first part of our polynomial. Ordering by exponent, our expression is now
Now let's do the same with the second term () and the third term (
).
- Adding on to our original expression:
- Adding on to our original expression:
Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.
This simplifies our expression down to .
Hope this helped!
Assuming the question is in the wrong format and"date" is data.
I chose X= 10,11,16,9,7,15,16,10 and Y= <span>96,51,62,58,89,81,46,51
the correlation cooefficent is -0.3351
</span>
I chose X= 10,11,16,9,7,15,16,10 and Y= <span>96,51,62,58,89,81,46,51
the correlation cooefficent is -0.3351
</span>
Using a system of equations, it is found that:
- For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
- For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
- For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
--------------------
The variables of the system are:
- x, which is the number of $29 tickets sold.
- y, which is the number of $34 tickets sold.
Total of 8,000 seats, all can be sold, thus:
--------------------
For a profit of $255,000, we have that:
For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
--------------------
For a profit of $271,000, we have that:
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
--------------------
For a profit of $235,000, we have that:
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
A similar problem is given at brainly.com/question/22826010