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ElenaW [278]
3 years ago
9

I need help with this question (Plz help asap)

Mathematics
2 answers:
notka56 [123]3 years ago
5 0
Hello!!

Area = length * width

So, Area = (8/15) * (1/6) = 4/45

Answer choice A is correct.

Hope this helps!! Let me know if you have ANY questions.
Sliva [168]3 years ago
4 0
The answer is a your right
You might be interested in
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
2r+2s=50<br> Please look at the picture
lidiya [134]

2r + 2s = 50

2r - s = 17

-----------subtract

3s = 33

s = 11

2r - s = 17

2r - 11 = 17

2r = 28

r = 14

so r = 14 and s = 11

answer is C. r = 14, s = 11

4 0
3 years ago
The value of x varies directly with y, and when x=1/3,y=5
pickupchik [31]

Answer: y = 36x

Step-by-step explanation: Given that x and y vary directly then the equation relating the is

y = kx ← k is the constant of variation

To find k use the condition x = , y = 12, then

k =  =  = 12 × 3 = 36

y = 36x ← equation of variation

3 0
3 years ago
Slope is - 4 and the line passes through the point (1,3 )​
Sergeeva-Olga [200]
Y = -4x + 7
This is the equation of the line. The slope is -4. The Y- intercept is 7
3 0
3 years ago
The endpoints of CD are C(−4, 7) and D(0,−3).
tino4ka555 [31]

Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})

Answer:

Midpoints of line CD are (-2,2).

Step-by-step explanation:

The midpoints is given by

Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})

As given

The endpoints of CD are C(−4, 7) and D(0,−3).

Putting values in the above

Midpoint =(\frac{0-4}{2},\frac{-3+7}{2})

Midpoint =(\frac{-4}{2},\frac{4}{2})

Midpoints = (-2,2)

Therefore midpoints of line CD are (-2,2).

4 0
3 years ago
Read 2 more answers
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