Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
2r + 2s = 50
2r - s = 17
-----------subtract
3s = 33
s = 11
2r - s = 17
2r - 11 = 17
2r = 28
r = 14
so r = 14 and s = 11
answer is C. r = 14, s = 11
Answer: y = 36x
Step-by-step explanation: Given that x and y vary directly then the equation relating the is
y = kx ← k is the constant of variation
To find k use the condition x = , y = 12, then
k = = = 12 × 3 = 36
y = 36x ← equation of variation
Y = -4x + 7
This is the equation of the line. The slope is -4. The Y- intercept is 7
Midpoint =(\frac{x_{2}+x_{1}}{2},\frac{y_{2}+y_{1}}{2})
Answer:
Midpoints of line CD are (-2,2).
Step-by-step explanation:
The midpoints is given by
As given
The endpoints of CD are C(−4, 7) and D(0,−3).
Putting values in the above
Midpoints = (-2,2)
Therefore midpoints of line CD are (-2,2).
