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3 years ago

I need help with this question (Plz help asap)

Mathematics

2 answers:

notka56 [123]3 years ago

5 0

Hello!!

Area = length * width

So, Area = (8/15) * (1/6) = 4/45

Answer choice A is correct.

Hope this helps!! Let me know if you have ANY questions.

Sliva [168]3 years ago

4 0

The answer is a your right

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Given h(t)=-2(t+5)^2+4, find h(-8) -334 -14 -45 -445

stepladder [879]

Substitute -8 for t in the expression, and now you have: h(-8) = -2[(-8) + 5]^2 + 4. Solve inside the parentheses; add -8 and 5.

h(-8) = -2[-3]^2 + 4, solve exponents next by squaring -3.

h(-8) = -2[9] + 4, multiply -2 and 9.

h(-8) = [-18] + 4, add -18 and 4.

h(-8) = -14.

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3 years ago

What is P(A and B)?

Sindrei [870]

Answer:

(A) 0.08

Step-by-step explanation:

P(A) = 0.8

P(B) = 0.1

P(A and B)

= 0.8 x 0.1

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6 0

3 years ago

Read 2 more answers

Find a parabola with equation y = ax2 + bx + c that has slope 5 at x = 1, slope −11 at x = −1, and passes through the point (2,

azamat

By "slope" I assume you mean slope of the tangent line to the parabola.

For any given value of x, the slope of the tangent to the parabola is equal to the derivative of y :

$y=ax^2+bx+c\implies y'=2ax+b$

The slope at x = 1 is 5:

$2a+b=5$

The slope at x = -1 is -11:

$-2a+b=-11$

We can already solve for a and b :

$\begin{cases}2a+b=5\\-2a+b=-11\end{cases}\implies 2b=-6\implies b=-3$

$2a-3=5\implies 2a=8\implies a=4$

Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when x = 2:

$4a+2b+c=18\implies2(2a+b)+c=10+c=18\implies c=8$

So the parabola has equation

$\boxed{y=4x^2-3x+8}$

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3 years ago

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Juli2301 [7.4K]

16% of 50 peaches is 8 peaches.

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3 years ago

If f(x) =2x-6 and g(x) =(x) -2x 2squared, find each value. 1. g(-1/3) 2. g(-1)

harina [27]

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4 years ago