A-b = 43----(1)
a+b = 13----(2)
(1)+(2) 2a=56
then a=56/2= 28
so b=13-28= -15
so that the numbers are -15 and 28
Step-by-step explanation:
<h2><u>Given :-</u></h2>
x-1-(x-1)²+ax-a
<h2><u>To find :-</u></h2>
Factorize the expression ?
<h2><u>Solution :-</u></h2>
Given expression is x-1-(x-1)²+ax-a
It can be written as
(x-1)-(x-1)²+(ax-a)
=> (x-1)-(x-1)(x-1)+a(x-1)
=> (x-1)[1-(x-1)+a]
=> (x-1)(1-x+1+a)
=> (x-1)(2-x+a)
<h2><u>Answer:-</u></h2>
x-1-(x-1)²+ax-a = (x-1)(2-x+a)
Hope this helps!!
one minute I'm doing the math
Answer:
b
Step-by-step explanation:
Step-by-step explanation:
use the midpoint formula
-3+-7/2, 8+-6/2
(-5, 1)
