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3 years ago

Which shows all the prime factors for 96?

Mathematics

2 answers:

KengaRu [80]3 years ago

7 0

That answer that you are looking for is D.

Mrrafil [7]3 years ago

5 0

the first two are not showing all prime factors

the third is only 48 and not 96

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Simplify -k-(3k-6n)+2n when k=-3 and n=-5

Mashutka [201]

Steps to solve:

-k - (3k - 6n) + 2n; k = -3, n = -5

~Substitute and simplify

-(-3) - (3(-3) - 6(-5)) + 2(-5)

3 - (-9 + 30)) - 10

~Use PEMDAS and solve the rest.

3 - 21 - 10

-18 - 10

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Best of Luck!

5 0

3 years ago

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andre [41]

Answer:51

Step-by-step explanation:

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3 years ago

numbers a and t are both rational numbers. number a is not the same distance as number t. are they opposites? why or why not?

Reika [66]

Answer:

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Step-by-step explanation:

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3 years ago

Which expression is equivalent to 5(d+1) a. 5d+5 b. 5d+1 c. d+5 d. d+6

Anettt [7]

I think the answer is A.

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5*1 = 5

That equals 5d + 1

Hope this helped

8 0

3 years ago

Prove that cos2α = 1-tan²α / 1+tan²α

Rufina [12.5K]

Answer:

see the explanation

Step-by-step explanation:

we have

$cos(2\alpha)=\frac{1-tan^2(\alpha)}{1+tan^2(\alpha)}$

Prove

Remember that

$cos(2\alpha)=cos^2(\alpha)-sin^2(\alpha)$

$tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}$

substitute in the expression above

$cos^2(\alpha)-sin^2(\alpha)=\frac{1-(\frac{sin(\alpha)}{cos(\alpha)})^2}{1+(\frac{sin(\alpha)}{cos(\alpha)})^2}$

$cos^2(\alpha)-sin^2(\alpha)=\frac{(\frac{cos^2(\alpha)-sin^2(\alpha)}{cos^2(\alpha)}}{(\frac{cos^2(\alpha)+sin^2(\alpha)}{cos^2(\alpha)}}}$

Remember that

$cos^2(\alpha)+sin^2(\alpha)=1$

Simplify

$cos^2(\alpha)-sin^2(\alpha)=cos^2(\alpha)-sin^2(\alpha)$ ---> is proved

4 0

3 years ago