<u>Given</u>:
The sum of 5 consecutive integers is 110.
Let the sequence be x, x + 1, x + 2, x + 3, x + 4
We need to determine the fourth number in the sequence.
<u>Value of x:</u>
Since, the sum of 5 consecutive integers is 110.
Thus, we have;

Adding the like terms, we have;



Thus, the value of x is 20.
<u>Fourth term:</u>
The fourth term of the sequence is x + 3
Substituting x = 20 in the term, we get;
Fourth term = 20 + 3 = 23
Thus, the fourth term of the sequence is 23.
Answer:
z = -3
Step-by-step explanation:
42 = -7 ( z-3)
42 = -7z + 21
21 = -7z
z = -3
Answer:
2789/36 is 77
with a remainder of 17
Step-by-step explanation:
Answer:
302
Step-by-step explanation:
For x = 4
7 x 4 + 49 = 77
Answer Is 77