Question

If

Answer 1

Answer:

t= 0

Step-by-step explanation:

Using the rules of logarithms

log x + log y = log(xy)

$log_{b}$ 1 = 0

Given

$log_{x}$ a + $log_{x}$ $\frac{1}{a}$ = t ,then

$log_{x}$ (a × $\frac{1}{a}$ ) = t

$log_{x}$ 1 = t , thus

t = 0

Answer 2

I’m pretty sure the answer is t=0