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ehidna [41]
3 years ago
7

Find the possibility of rolling even numbers three times, using a six-side die number from 1 to 6

Mathematics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

\frac{1}{8}

Step-by-step explanation:

Number of sides of die = 6

Number of sides with even numbers = 3

P( rolling an even number 1 time) = \frac{3}{6} = \frac{1}{2}

P(rolling even number 3 times) = \frac{1}{2} x \frac{1}{2}  x \frac{1}{2} = \frac{1}{8}

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A study of 138 penalty shots in World Cup Finals games between 1982 and 1994 found that the goalkeeper correctly guessed the dir
vladimir2022 [97]

Answer:

z=-2.09

Step-by-step explanation:

Given that a study  of 138 penalty shots in World Cup Finals games between 1982 and 1994 found that the goalkeeper correctly guessed the direction of the kick only 41% of the time.

Set up hypotheses as:

H_0: p=0.50\\H_a: p

(left tailed test at 5% significance level)

Standard error = 0.043

Sample proportion p = 0.41

p difference = 0.41-0.50=-0.09

Test statistic Z = p diff/std error

= \frac{-0.09}{0.043} \\=-2.09

Z = -2.09

4 0
3 years ago
Which values of m and b will create a system of equations with no solution? Check all that apply. y = mx + b y = –2x + 3/2
Leni [432]
Lines with no solution are parallel lines....parallel lines will contain the same slope, but different y intercepts.

y = -2x + 3/2....slope (m) = -2 and y int (b) = 3/2
so the line we need will have a slope of -2, but can have any y int EXCEPT 3/2.

m = -2, and b = -1/3 is parallel, no solution
m = -2 and b = -2/3...parallel, no solution
7 0
4 years ago
Read 2 more answers
How many groups of 2/3 are in three
Lesechka [4]
2 groups is the answer
6 0
4 years ago
Solve x/2 - 3 = 7. 5 10 20 40
earnstyle [38]
<span> x/2 - 3 = 7
Add 3 to both sides
x/2=10
Multiply 2 on both sides
Final Answer: B. 20</span>
3 0
3 years ago
Read 2 more answers
(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28
Veronika [31]

(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}

4 0
4 years ago
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