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kondaur [170]
2 years ago
9

Which of the following is the inverse of y = 12 Superscript x? y = log Subscript one-twelfth Baseline x y = log Subscript 12 Bas

eline StartFraction 1 Over x EndFraction y = log Subscript x Baseline 12 y = log Subscript 12 Baseline
Mathematics
1 answer:
wariber [46]2 years ago
3 0

Answer:

y = lnx/ln12

Step-by-step explanation:

Given the function y = 12^x, to find the inverse of the function, we news to write x as a function of y as shown:

Given y = 12^x

Taking ln of both sides

ln y = ln 12^x

ln y = xln12

Divide both sides by ln12

lny/ln12 = xln12/ln12

x = lny/ln12

x = ln(y-12)

Replacing y with x and x with y

The inverse of the function will be:

y = lnx/ln12

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umka21 [38]

The complete question is

"A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.

What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame?

16.7°, 17.5°, 72.5°,73.3°"

The value of angle x would be 16.7 degrees.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

The angle of a right angle is always 90 degrees.

In order to find the value of x, a tan would be used.

This is because we have given the opposite and adjacent sides as 10 ft and 3 ft.

Tan Ф = opposite / adjacent

Tan Ф =  (3/10)

= 16.7 degrees

The value of angle x would be 16.7 degrees.

Learn more about a right angle;

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1 year ago
How can you tell from a table of values if a relationship is proportional?
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10 pts<br> Point K (-2,-3) is translated (x + 5, y-7). What are the coordinates K?
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The nth term of a sequence is 3n²-1
Anarel [89]

Answer: The number is 26.

Step-by-step explanation:

We know that:

The nth term of a sequence is 3n²-1

The nth term of a different sequence is 30–n²

We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.

we get:

3n²- 1 =  30–m²

Notice that as n increases, the terms of the first sequence also increase.

And as n increases, the terms of the second sequence decrease.

One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.

if m = 1, then:

3n²- 1 =  30–1²

3n²- 1 = 29

3n² = 30

n² = 30/3 = 10

n² = 10

There is no integer n such that n² = 10

now let's try with m = 2, then:

3n²- 1 =  30–2² = 30 - 4

3n²- 1 = 26

3n² = 26 + 1 = 27

n² = 27/3 = 9

n² = 9

n = √9 = 3

So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.

the number is:

3*(3)² - 1 = 26

30 - 2² = 26

The number that belongs to both sequences is 26.

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2 years ago
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solong [7]

Answer:

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Step-by-step explanation:

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