Question

SOLVE EACH EQUATION BY TAKING SQUARE ROOTS. 1.) 3(x-5)^2=48 2.)2x^2-56=42

Answer 1

Answer:

see explanation

Step-by-step explanation:

(1)

3(x - 5)² = 48 ( divide both sides by 3 )

(x - 5)² = 16 ( take the square root of both sides )

x - 5 = ± $\sqrt{16}$ = ± 4 ( add 5 to both sides )

x = 5 ± 4

Thus

x = 5 - 4 = 1

x = 5 + 4 = 9

Solutions are x = 1, x = 9

(2)

2x² - 56 = 42 ( add 56 to both sides )

2x² = 98 ( divide both sides by 2 )

x² = 49 ( take the square root of both sides )

x = ± $\sqrt{49}$ = ± 7

Solutions are x = - 7, x = 7