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4 years ago

Neeeed helpp!!!! thank you

Mathematics

1 answer:

Elena L [17]4 years ago

3 0

Answer:

1: 12d

2: m^-2 n^3

Step-by-step explanation:

For problem 1, you subtract all of the exponent(s) for 4d^4 by adding -4 and 4 together to create zero, thus removing the exponent(s), then you multiply 3×4 and get 12d.

For problem 2, you just put m^-2 and n^3 together. You cannot combine the exponents or variables, so it would just look like m^-2 n^3

The ^ before a number means that it is an exponent.

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3 years ago

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3 years ago

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3 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

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3 years ago

What is the 25th term of this arithmetic sequence? 3, 9, 15, 21, 27, …

irga5000 [103]

An = a1 + (n - 1)(d)
a1 = the first term in the sequence
d = common difference
n = term
a25 = 3 + (25 - 1)(6)
a25 = 3 + (24)(6)
a25 = 3 + 144
a25 = 147

8 0

4 years ago

Read 2 more answers