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jeka94
2 years ago
10

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

graphical errors on a page of second booklet is a Poisson random variable with mean 0.3. Suppose the number of errors on different pages of the same or different booklets is independent. There are 7 pages in the first booklet and 5 pages in the second one. Find the probability of more than 2 typographical errors in the two booklets in total.
Mathematics
1 answer:
muminat2 years ago
4 0

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

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4 3/4 divided by 1 1/6
ozzi

Answer:

2\frac{13}{22}

Step-by-step explanation:

=\frac{19}{4}\div \frac{11}{6}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{19}{4}\times \frac{6}{11}

=\frac{19}{2}\times \frac{3}{11}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{19\times \:3}{2\times \:11}

\mathrm{Multiply\:the\:numbers:}\:19\times \:3=57

=\frac{57}{2\times \:11}

\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22

=\frac{57}{22}

=2\frac{13}{22}

5 0
2 years ago
A soccer goal is 24 feet wide. Point A is 40 feet in front of the center of the goal. Point B is 40
Liono4ka [1.6K]

Answer:

a) Angles A and B are 90 degree.

b) The 2 angles are equal

c) From point A having a better chance to kicking the ball in to goal

Step-by-step explanation:

a, b) 2 points are in front of the center and right post of goal. Because there is no detail, we can assume that point A, point B, center of goal, right goal post make up a rectangle. Therefore, the 2 angles are measured equally as 90 degree.

c) Because it's a rectangle, the distance between point A and center of goal is shorter than that between point B and center of goal.

3 0
2 years ago
120 miles in 1 3/4 hours as a unit rate
Zarrin [17]

9514 1404 393

Answer:

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Step-by-step explanation:

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2 years ago
Can somebody help me with this?
Bess [88]
The answer is C, 40, angle c for triangle abc is 50 bc the total of it and 130 must equal 180. so if you subtract the angle you are given, 90, and the new angle, 50, from 180 (total a triangle should have) then your answer is 40.
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3 years ago
What two numbers have a sum of 217 and a difference of 85?
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We can use the system of equations:x + y = 217x - y = 85-----------------From the 2nd equation:  y = x - 85x + x - 85 = 2172 x = 217 + 852 x = 302x = 302 : 2x = 151y = 217 - 151y = 66We can prove this solution:151 + 66 = 2017   and  151 - 66 = 85.Answer: those numbers are 151 and 66.

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3 years ago
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