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Klio2033 [76]
4 years ago
11

Enter your answer in the box.

Mathematics
1 answer:
TEA [102]4 years ago
8 0
This is an arithmetic series,
so 
S(n) = (n/2)*(a(1)+a(n))
S(25) = (25/2)*(a(1)+a(25))
n=25
a(n) = 3n-2
a(1)= 3*1-2=1
a(1)=1
a(25) = 3*25-2=75-2=73
a(25)=73

S(25) = (25/2)*(1+73)=(25/2)*74=925
S(25)=925

Answer : 925
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6<br><br><br> math geniuses help please!!<br><br><br> math
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Answer:

A

Step-by-step explanation:

Begin with Euler's formula. I am assuming youre aware of this if youre taking complex algebra? You can prove Euler's formula by doing a Maclaurin expansion of cosine, sine, and e^x. Euler's formula states that:

e^{ix}=cos(x)+isin(x)

We can put the first complex number in exponetial form by noticing the input is 2pi/3. The second complex number has an input of pi/3. Therefore:

z_1=8e^{i(2\pi /3)}

z_2=0.5e^{i(\pi /3)}

Then:

\frac{z_1}{z_2} =\frac{8e^{i(2\pi /3)}}{0.5e^{i(\pi /3)}}

Simplify the coefficients to get:

\frac{z_1}{z_2} =\frac{16e^{i(2\pi /3)}}{e^{i(\pi /3)}}

When you divide exponentials, you subtract the exponents. Therefore:

\frac{z_1}{z_2} =16e^{i(2\pi /3)-i(\pi /3)}=16e^{i(\pi /3)

Put it back into trigonemtric form using Euler's formula:

16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)

Cosine of pi/3 is 0.5, and sine of pi/3 is square root of 3 over 2. We have:

16e^{i(\pi /3)}=16cos(\pi /3)+i16sin(\pi /3)=16*0.5+16*\frac{\sqrt{3} }{2} *i=8+8\sqrt{3} i

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pychu [463]
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____________________________________


Glad I could help, and good luck!

8 0
3 years ago
Help me please I need this
OleMash [197]

Answer:

The answer is A

Step-by-step explanation:

I take test bfor.

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