Answer:
the answer would be 2(3-x)
Step-by-step explanation:
x would be the number that is given and since it says twice than 2 would be outside the parenthesis since the main equation would be inside the parenthesis
Total area = 9 x5 =45
Total area = (6+3)(4+1)=24+6+12+3=45
ABCD is a square . if the coordinates of three of its vertices are A(-1,2a), B(a,2a), C(a,0), find the coordinates of D. BC is obviously 2a (it's a vertical line) then AB must be 2a (notice AB is horizontal) so BC = AC because it is a square 2a = a+1 a=1
Answer:
D)
Step-by-step explanation:
f(x) = x^2 -14x -72
0=x^2 - 14x-72
0=x^2 - 18x+4x-72
0=x(x-18)+4(x-18)
0=(x-18)(x+4)
x-18=0 or x+4=0
x1=18 or x2=-4
asis of symmetry: x=(x1+x2)/2
x=(18+(-4))/2
x=14/2
x=7
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
