a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
x=-4/3
Step-by-step explanation:
3x-12=12x
3x-12x=12
-9/-3=12/-3
then -3 cancels
3x/3=-4/3
then 3 cancels 3
so x=-4/3
Answer: (10,9) is the correct answer.
Answer:wanted to help but not that smart
Step-by-step explanation:
Answer:

Step-by-step explanation:

Step 1: Apply exponent rule: 

Step 2: Multiply fractions: 

Step 3: Simplify

The result is 
<u>Spanish/Espanól</u>
Respuesta:
Explicación paso a paso:
Paso 1: aplique la regla del exponente:
Paso 2: multiplica fracciones:
Paso 3: simplifica
El resultado es 