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3 years ago

3. What are the three ways that a person can manipulate light?

Computers and Technology

1 answer:

ASHA 777 [7]3 years ago

3 0

Answer:

reflect, shadow, move subject

Explanation:

hope this helps

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8.11 LAB: Filter and sort a list

Helen [10]

nums = input("Enter your numbers: ")

lst = nums.split()

new_lst = ([])

for i in lst:

if int(i) >= 0:

new_lst.append(int(i))

new_lst.sort()

for x in new_lst:

print(x, end=" ")

The above code is in case the user enters the numbers.

def func(lst):

lst.sort()

for i in lst:

if i >=0:

print(i, end=" ")

lst = ([10,-7, 4, 39, -6, 12, 2])

func(lst)

The above code is in case you must input the numbers manually via a function.

I hope this helps!

6 0

3 years ago

How can a user preview the playback of an audio clip in PowerPoint? Use the drop-down menus to complete the statements.

tresset_1 [31]

Answer:

Playback

Preview

Slide show

From Current Slide

Explanation:

7 0

3 years ago

Andy is trying to put together a holiday gift knapsack (with W=8) for Sarah. He has n items to choose from, each with infinitely

Sever21 [200]

Answer:

See explaination

Explanation:

Given 3 items: {w1 = 1, v1 = 3}, {w2 = 3, v2 = 2}, {w3 = 4, v3 = 3}

Hence OPT(1) = 3, OPT(3) = 2, OPT(4) = 3

Recursive formula for OPT(k) to minimize value is

OPT(k) = INFINITE if k <= 0

= min(3 + OPT(k-1), 2 + OPT(k-3), 3 + OPT(k-4))

Let us calculate OPT(1) to OPT(8)

OPT(1) = 3

OPT(2) = min ( 3 + OPT(1), 2 + OPT(-1), 3 + OPT(-2)) = 6

OPT(3) = 2

OPT(4) = 3

OPT(5) = min ( 3 + OPT(4), 2 + OPT(2), 3 + OPT(1)) = min(6, 8, 6) = 6

OPT(6) = min ( 3 + OPT(5), 2 + OPT(3), 3 + OPT(2)) = min(9, 4, 9) = 4

OPT(7) = min ( 3 + OPT(6), 2 + OPT(4), 3 + OPT(3)) = min(7, 5, 5) = 5

OPT(8) = min ( 3 + OPT(7), 2 + OPT(5), 3 + OPT(4)) = min(8, 8, 6) = 6

3 0

3 years ago

Draw a circuit with a 12-volt battery, a 100 ohms resistor in series, and two resistors (each of value 200 ohms) in parallel. Wh

amid [387]

Answer:

200 Ω

Explanation:

Hi there!

Please see below for the circuit diagram.

1) Find the total resistance of the resistors in parallel

Total resistance in parallel equation: $\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2}$

Both the resistors measure 200 Ω. Plug these into the equation as R₁ and R₂:

$\frac{1}{R_T} = \frac{1}{200} +\frac{1}{200}\\\frac{1}{R_T} = \frac{1}{100}\\R_T=100$

Therefore, the total resistance of the resistors in parallel is 100 Ω.

2) Find the total resistance of the circuit

Now, to find the total resistance of the circuit, we must add the 100 Ω we just solved for and the 100 Ω for the other resistor placed in series:

100 Ω + 100 Ω = 200 Ω

Therefore, the total resistance of the circuit is 200 Ω.

I hope this helps!

7 0

3 years ago

Why it is so important for all application builders to always check data received from unknown sources, such as web applications

Aleks04 [339]

The already-long problem on hacking and other security-related cases necessitates for the application builders to check the data received from unknown sources. To further strengthen the security, even data received from known sources also need to be check as these may also contain harmful viruses creating critical problem to the application.

6 0

3 years ago