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3 years ago

Help please with 9 and 10 please !

Mathematics

2 answers:

malfutka [58]3 years ago

5 0

Answer:

9) The scale factor is 3/2

10) The scale factor is 4/3 and the missing length is 9

Step-by-step explanation:

9) The triangles are similar because 6/4 = 9/6 = 3/2

The scale factor is 6/4 = 3/2

10) If the rectangular gardens are similiar then the scale factor is 16/12 = 4/3

(The scale factor is always > 1)

=> 12 / x = 4/3 => 4x = 12·3 => x = 9

Lana71 [14]3 years ago

3 0

Answer:

9. The scale factor is 1.5.

10. scale factor = 0.75

the missing side is 9m

Step-by-step explanation:

9. 3/2 = 1.5

9/6 = 1.5

6/4 = 1.5

10. 12/16 = 0.75

12*0.75 = 9

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What is the difference of the polynomials? (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

ANEK [815]

For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= −6x4y−2x3y2+9x2y3−3xy4+y5

I hope this helps

4 0

3 years ago

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2 years ago

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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago

In need help please fast

slava [35]

Answer:

hope it helped u alot

Step-by-step explanation:

plsss give me braniest

8 0

3 years ago

Hey I need these by 8am or I'm screwed,

tiny-mole [99]

34.4 / 4 = 8.6

The value 214.01 is greater.

2.5 x 10^3 = 2,500

1 M = 100 CM
2 M = 200 CM
3 M = 300 CM
4 M = 400 CM
5 M = 500 CM
6 M = 600 CM
7 M = 700 CM

If you want detailed explanations after you get done with your classes ill be glad to explain. Happy studying!

5 0

3 years ago