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Nezavi [6.7K]
3 years ago
5

Help please with 9 and 10 please !

Mathematics
2 answers:
malfutka [58]3 years ago
5 0

Answer:

9) The scale factor is 3/2

10) The scale factor is 4/3 and the missing length is 9

Step-by-step explanation:

9) The triangles are similar because 6/4 = 9/6 = 3/2

The scale factor is 6/4 = 3/2

10) If the rectangular gardens are similiar then the scale factor is 16/12 = 4/3

(The scale factor is always > 1)

=> 12 / x = 4/3 => 4x = 12·3 => x = 9

Lana71 [14]3 years ago
3 0

Answer:

9. The scale factor is 1.5.

10. scale factor = 0.75

    the missing side is 9m

Step-by-step explanation:

9. 3/2 = 1.5

   9/6 = 1.5

   6/4 = 1.5

10. 12/16 = 0.75

    12*0.75 = 9

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What is the difference of the polynomials?<br><br> (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)
ANEK [815]
For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= <span><span><span><span><span>−<span><span>6x4</span>y</span></span>−<span><span>2x3</span>y2</span></span>+<span><span>9x2</span>y3</span></span>−<span>3xy4</span></span>+y5</span> 

I hope this helps
4 0
3 years ago
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(21.) A writer earns $3400 a month. Last month she spent $204 on food.
Sergeu [11.5K]
6 percent was spent
7 0
2 years ago
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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

Now, let's replace the previous result into \frac{\partial f(x,y)}{\partial y}=Q(x,y) :

cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

Solving for \frac{dg(y)}{dy}

\frac{dg(y)}{dy}=sin(y)

Integrating both sides with respect to y:

g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

7 0
3 years ago
In need help please fast
slava [35]

Answer:

hope it helped u alot

Step-by-step explanation:

plsss give me braniest

8 0
3 years ago
Hey I need these by 8am or I'm screwed,
tiny-mole [99]
34.4 / 4 = 8.6 

The value 214.01 is greater.

2.5 x 10^3 = 2,500

1 M = 100 CM
2 M = 200 CM
3 M = 300 CM
4 M = 400 CM
5 M = 500 CM
6 M = 600 CM
7 M = 700 CM

If you want detailed explanations after you get done with your classes ill be glad to explain. Happy studying!

5 0
3 years ago
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