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denis-greek [22]
3 years ago
10

Please I need help will mark brainliest

Mathematics
2 answers:
Vlad1618 [11]3 years ago
6 0

Answer:

Arc JK: 27°

Arc NJ: 153°

Arc JL: 117°

My guess on arc KNM is 207°

My other guess for MJL is 297

JKM 180°

Step-by-step explanation:

Vsevolod [243]3 years ago
3 0
Fndjjrejjr rjejejepoop
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What is the height of a solid with a volume of 120m and base area of 30m
igor_vitrenko [27]

Answer:

4m.

Step-by-step explanation:

Divide the total volume by the base area to find the height. This is because the volume of a solid is equal to the base area multiplied by the height.

120/30=4

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3 years ago
Find the derivative
zalisa [80]

First use the chain rule; take y=\dfrac{x+5}{x^2+3}. Then

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}

By the power rule,

f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}

By the quotient rule,

y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}

So

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}

\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}

6 0
3 years ago
Coach Withrite can bench press 325 lbs. How many kg can he bench?
puteri [66]

Answer:

147.18 Kgs

Step-by-step explanation:

1 Kg= 2.2 lbs

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147.18 Kgs

<em>Hope his helped! Have a good day!</em>

<em>All rewards appreciated!</em>

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Step-by-step explanation:

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