The area of a sector = 0.5 * radius^2 * central angle measure (in radians)
So that:
![Area_{sector}= \frac{1}{2} * 6^2* \frac{120}{180}*\pi=12\pi=37.69911 \\ Area_{sector}=37.7](https://tex.z-dn.net/?f=Area_%7Bsector%7D%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%2A%206%5E2%2A%20%5Cfrac%7B120%7D%7B180%7D%2A%5Cpi%3D12%5Cpi%3D37.69911%0A%5C%5C%0AArea_%7Bsector%7D%3D37.7%20%20%20)
sq in
Answer:
54.22 mm
Step-by-step explanation:
Find the circumference of the circle and then divide it by 2.
We start with the formula for the circumference for the circle:
C = 2πr
To find r, divide 22 by 2:
22/2=11
Now find the cicumference:
C = 2πr = 2(3.14)(11) = 108.46 mm
NOW, to find the perimeter of the semicircle, divide the circumference by 2:
108.46/2 = 54.22 mm