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Rama09 [41]
3 years ago
8

1/4 + 1/2 +x=-3/4. Solve for x

Mathematics
2 answers:
charle [14.2K]3 years ago
7 0

Answer:

x= <u>-</u><u>6</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>-</u><u>3</u>

<u> </u><u> </u> 4 or 2

Step-by-step explanation:

1/2=2/4

2/4+1/4+6=-3/4

3/4+x=-3/4

subtract 3/4 on both sides

3/4+x=-3/4

-3/4. -3/4

x=-6/4

simplified x=-3/2

ryzh [129]3 years ago
3 0

Step-by-step explanation:

1/4 + 1/2 + x = -3/4

1/4 + 2/4 + x = -3/4

3/4 + x = -3/4

-3/4. -3/4

x = - 1 1/2

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Find the length of the following curve. If you have a​ grapher, you may want to graph the curve to see what it looks like.
stepladder [879]

The length of the curve y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6

Start by differentiating the curve function

y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x

Evaluate

y' = x(9x^2 + 6)^\frac 12

The length of the curve is calculated using:

L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx

This gives

L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx

Expand

L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx

This gives

L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx

Express as a perfect square

L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx

Evaluate the exponent

L =\int\limits^6_3 {3x^2 + 1} \ dx

Differentiate

L = x^3 + x|\limits^6_3

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

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2 years ago
Help ur bestie out plzzz (puppy eyes) and show me how u got the answer thx
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I think the answer is D. But I am not sure if that's the right answer.

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2 years ago
(5÷3)x+(1÷2)=0 <br><br>find x​
xxMikexx [17]
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4 years ago
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Answer:

{-3,2,5}

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Step-by-step explanation:

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