Complete the equation involving x. Order terms like the physical situation, and don't simplify. A 6 foot wide painting should be
centered on a 10 foot wide wall. How many feet (x) should be on each side of the painting?
1 answer:
Answer:
The space on each side of the painting = 2 feet
Step-by-step explanation:
Attached this answer is a diagram to give you visuals on how the value of x is calculated
Given:
width of wall = 10 feet
width of painting = 6 feet
Since the painting is centred on a wall, there is meant to be an equal space on each side of the painting, from the diagram, the following eaquation can be gotten
x + 6 + x = 10
2x + 6 = 10
2x = 10 - 6
2x = 4
x = 4 ÷2
x = 2 feet
Therefore, the space on each side of the painting = 2 feet
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Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are
The volume of the box is equal to
so
simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A
solve for y
Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x
therefore
The original length was 41 inches and the original width was 16 inches
