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Ilya [14]
3 years ago
15

Which of the following is the maximum value of the equation y=-2x^2-3x+4

Mathematics
1 answer:
mylen [45]3 years ago
4 0
Y=-2x^2-3x+4

dy/dx=-4x-3, d2y/dx2=-4

When the velocity, dy/dx=0, then y(x) is at an absolute maximum because the acceleration is a constant negative, -4.

dy/dx=0 only when -4x-3=0, -4x=3, x=-3/4

y(-3/4)=5.125

So the maximum value of y is 5 1/8
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marishachu [46]

Answer:

1 pear = $0.75; 1 orange = $0.65

Step-by-step explanation:

(1)               3P +  4O = 4.85

(2)              3P + 10O = 8.75                 Eqn (2) - Eqn (1)

3P + 10O – 3P – 4O = 8.75 – 4.85     Combine like terms

                           6O = 3.90                 Divide each side by 6

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               3P + 2.60 = 4.85                 Subtract 2.60 from each side

                           3P = 2.25                Divide each side by 3

                            P = $0.75

Oranges cost $0.65 each and pears are $0.75 each

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Step-by-step explanation:

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