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Ilya [14]
3 years ago
15

Which of the following is the maximum value of the equation y=-2x^2-3x+4

Mathematics
1 answer:
mylen [45]3 years ago
4 0
Y=-2x^2-3x+4

dy/dx=-4x-3, d2y/dx2=-4

When the velocity, dy/dx=0, then y(x) is at an absolute maximum because the acceleration is a constant negative, -4.

dy/dx=0 only when -4x-3=0, -4x=3, x=-3/4

y(-3/4)=5.125

So the maximum value of y is 5 1/8
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