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snow_tiger [21]
3 years ago
5

The sum of three consecutive odd numbers is 57. What are the three numbers?

Mathematics
1 answer:
RSB [31]3 years ago
3 0

Answer:

The 3 numbers are 17,19 and 21

Step-by-step explanation:

Hope this helps!

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Whats the quotient of 15.86 divided by 0.65?
spayn [35]

Answer:

24.4

Step-by-step explanation:

15.86 /0.65 = 24.4

8 0
3 years ago
3x + 2(4x - 4) = 3 <br><br><br><br> HELPPPPPPPP!!!!!!!
PilotLPTM [1.2K]

Answer:

x=1

Step-by-step explanation:

Use the distributive property on 2(4x - 4), which makes the equation 3x+8x-8=3

Simplify, which makes the equation 11x-8=3

Add 8 to both sides, which makes the equation 11x=11

Divide both sides by 11, which makes the equation x=1

3 0
3 years ago
Create a data set with 10 numbers that has a mean of 32?
densk [106]
30,77,55,71,19,40,10,5,7,6
4 0
2 years ago
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi
stealth61 [152]
Applying our power rule gets us our first derivative,

\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}

simplifying a little bit,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

looking for critical points,

\rm 0=2x^{-2/3}+4x^{1/3}

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

0=2x^{-2/3}\left(1+2x\right)

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

\rm f'(x)=2x^{-2/3}+4x^{1/3}

and take our second derivative.

\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}

Looking for inflection points,

\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}

Again, pulling out the smaller power of x, and fractional part,

\rm 0=-\frac43x^{-5/3}\left(1-x\right)

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
8 0
3 years ago
A student fond the slope of a line that passes through the points (-8,-6) and (2,-3) to be 3/10. what mistake did she make?
goldfiish [28.3K]
Simple ....

we know to find slope is (y1-y2)/(x1-x2)

if we plug in what we know......

(-8,-6),(2,-3)

(-6--3)/(-8-2)

it turns into...

(-6++3)/(-8+-2)

(-3)/(-10)= 3/10

Thus, your answer is that she made no mistake. (C)
4 0
3 years ago
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